برامج السي++ مع التحليل العددي

نيوتن
#include>
#include>
#include>
void main()
{
clrscr();
//f(x)=x^3+2x^2+10x-20
// a=1
// b=2
//*************
double x1,x2,x3,x4,x5,x6;
double a,b,c,d,f,g;
double fx1,mfx1,fx2,mfx,fx3,mfx3,fx4,mfx4,fx5,mfx5;
int n,m;
cout<<"Enter Number Of Iteration:"<<"\n";
cin>>a>>b>>c>>d>>f;
cout<<"Enter tow point :"<<"\n";
cin>>n>>m;
cout<<"Enter Initial point :"<<"\n";
cin>>x1;
cout<<" x1 "<<" x2 "<<" x3 "<<" x4 "<<" fx4 "<< "\n";
cout<<"............................"<<"\n";
for(int i=1;i<=n;i++)
{
fx1=pow(x1,3)+2*pow(x1,2)+10*x1-20;
mfx=3*pow(x1,2)+4*x1+10;
x2=x1-(fx1/mfx1);
fx2=pow(x2,3)+2*pow(x2,2)+10*x2-20;
cout<<<" ";
cout<";
if(fx2<=0.00001)
{
cout<<"root="<;
break;
x1=x2;
}
cout<<"\n";
}
getch();
}
طريقه التنصيف
#include>
#include>
#include>
void main()
{ clrscr();
//x^3+x^2-3*x-3
//a=1 b=2
double x1,x2,x3;
double fx1,fx2,fx3,fx1fx2,fx;
float a,b;
int i,n;
cout<<"Enter tow point:"<<"\n";
cin>>a>>b;
x1=a;
x2=b;
cout<<"Enter iterlation:"<<"\n";
cin>>n;
cout<";
cout<<".........................."<<"\n";
for(i=1;i<=n;i++)
{
fx1=pow(x1,3)+pow(x1,2)-3*x1-3;
fx2=pow(x2,3)+pow(x2,2)-3*x2-3;
fx1fx2=fx*fx2;
x3=x2-((fx*(x2-x1))/(fx2-fx1));
fx3=pow(x3,3)+pow(x3,2)-3*x3-3;
cout<";
if(abs(fx3)==0.00001)
{
cout<<"The point Is:"<";
break;
}
else if(fx1fx2>0.0)
{
x1=x1;
x2=x3;
}
else x1=x3;
x2=x2;
}
getch();

}
الصامده
[size=25]
#include>
#include>
#include>
void main()
{ clrscr();
//f(x)=x^3+2*x^2+10*x-20
//a=1
//b=2
//xn=(20-x^3)/(2*x+10(
double x0,x1,fx1,fx;
float point,a,b;
int i,n;
cout<<"Enter number of iteration:"<<"\n";
cin>>n;
cout<<"Enter Tow points:"<<"\n";
cin>>a>>b;
cout<<"Enter Initial points:"<<"\n";
cin>>point;
cout<<"\n";
x0=point;
cout<<" x0 "<<" x1 "<<" x2 "<< " "<";
cout<<"//........................................................//"<<"\n";
for(i=1;i<=n;i++)
{
x1=((20-pow(x0,3))/(2*x0+10));
fx=pow(x1,3)+2*pow(x1,2)+10*x1-20;

cout<<" "<
<<"\n";
// if(x1>=a&&x1<=b)
if(abs(fx1)==0.00001)//abs(fx1)==0)
{
cout<<"root "<";
break;
}
x0=x1;
}
getch();
}

بعض البرامج
[size=29]
#include>
#include>
class student {
private:
int *x;
public:
int no;
char*name;
student(){
cout<<"x=";
cin>>*x;}
~student(){cout<<" "<<"******"<<"delete(x)";}
int show(){
return(*x);};};
main(){
clrscr();
student p;
cout<<"entre the number"<<"\n";
cin>>p.no;
cout<<"entre the name"<<"\n";
cin>>p.name;
p.show();
cout<();
getch();}

[/size][/size]

#include>
#include>
struct s3{
int no;
char *name;
};
main(){
s3 x;
x*ptr.p;
ptr=&a;
ptr=&p;
cout<<"ente name";
cin>>x.name;
cout<<"enter no" ;
cin>>x.no;
cout<no<<""<name<<""<;
getch();}
#include>
#include>
struct s1{
char *name;
int no;
float deg;
};
main(){
struct s1 a[5];
for(int i=1;i<=5;i++){
cout<<"enter name";
cin>>a[i].name;
cout<<"enter no";
cin>>a[i].no;
cout<<"enter deg";
cin>>a[i].deg;
cout<; }
getch();
}
#include>
#include>
struct s1{
int no;
char *name;
float deg;
};
struct s2{
int x;
s1 f;};
main(){
clrscr();
struct s2 r;
cout<<"enter name /n";
cin>>r.f.name;
cout<<"enter no /n";
cin>>r.f.no;
cout<<"enter deg /n;";
cin>>r.f.deg;
cin>>r.x;
cout<<" "<";
getch();
}
#include>
#include>
class c1{
int x;
protected:
int y;
public:
c1(){}
void setxy(){
cin>>x>>y;
}
void show(){
cout<;
}
int z;
} ;
class c2:public c1{
int n;
public:
c2(){}
void get_n(){
cin>>n;
}
void show_ynx()
{
cout<;
void show_x();
};
void main(){
clrscr();
c2 ob1 ;
ob1.z=5;
ob1.setxy();
ob1.get_n();
ob1.show_ynx();
cout<;
cout<;
getch();
}

[b]

#[font=Arial]include

struct s3{

int no;

char *name;

};

main(){

s3 x;

x*ptr.p;

ptr=&a;

ptr=&p;

coutx.name;

coutx.no;

[font=Arial][size=25][right]cout

» طريقة نيوتن في التحليل العددي
» السي ++
» التحليل النوعي أو الوصفي
» روائع الاعجاز العددي في القران الكريم
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